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Welcome to my homepage, developing the classic main physics
Particle radiation

If you have not put yourself into what micro physics is, then understanding the basis for this section is not present.
You may read the following link and ensure you understand the contents.
Universe, Classic big bang and Micro physics

In the micro-physics I use radiation is a light beam also called a high speed particle. It is not because I have anything against wave physics as such, but it is necessary to see the universe as a complete evolving system where there is a connection between mass, particles and also radiation. Radiation as wave physics does not fit into the universe development machine.

Radiation is one of the universe's fundamental building blocks and is included in all physical connections.
I will show an interesting example which should give you something to think about.
A blacksmith is knocking on a piece of iron, the iron becomes hot and emits infrared light. The smith has just by knocking on a piece of iron reached the speed of light.
When a particle decelerate it will always give its energy back in form of radiation.

Here I show a picture of the most common way to split a light beam on.
Scattering of photons come when the light is deflected by the atomic nucleus mass attraction. The places where there is impact of photons spectral points appears, the rest of the tape is black (nothing).

There are two branches of radiation physics (particle and wave physics). The branch that I use is a further development of the particle branch.
You should be aware that there is a big difference of the two branches interpretation of the properties of light.
When a particles velocity becomes larger, its properties will be changed. When a particle reach the speed of light, we get a very long particle as I call a light beam but it still have has the same particle properties.

A light beam has mass deflection properties and is a variant in the universe's particle system.

To calculate a light beams energy, it is necessary to calculate it from the light beam standard length c, with the Max Planck method.

All particles have a built-in system to absorbing and emitting radiation. The way the system works on is that it is not the whole string length emitted but little bits each having the same properties as a whole light beam. The string's properties can be determined (wavelength and frequency) by using the light beam mass attractiveness properties, see the following figure.

A light beam deflected in a force field Fig. f 32

On the photon's transverse axis there is normal particle properties.
Therefore, it is possible because of the mass attraction between two particles to calculate the light beam's deflection.

If we send some light with different wavelengths from point A, the light will arrive at point B with arrival times which is longer than if the light beam is send in a straight line (light speed is c).

We observe it as if light hesitates. The light is an exact size that always moves with speed c (it is one of most important functions in the universe, see other sections).

The light hesitation has been known for some years. The definition is that the speed of light c applies only to light in vacuum. The explanation will people behind wave physics accept, but to us who see the light as a particle the explanation can not be accepled. There are several reasons why this is interesting, among other things, we want to know how light interacts with nuclear material when it moves in solids, for example. can we remove radiation loss in a conductor then we have a superconductor.

A particle radiation system
A particle is composed of the basic nucleis as also the atomic nucleus is composed of . It is the basic nuclei which treats radiation and is the universes main building blocks. If a particle had no basis nuclei the particle would neither have any absorption and emission system.

It will take a second to create a light beam with the length c which is a very large time in the world of atoms.
The basic nucleus starts to emitters one light beam, but before it has reached to send the entire string, it absorb another light beam. The two amounts of energy amouts and the whole process starts over again.

The basic nucleus emits therefore light beam into small pieces, where all every has the same properties as a whole light beam.
Of physical and mathematical reasons it is necessary to calculate the entire the light beam´s length to find the light beam´s diameter as it interacts with mass.
A base nucleus can be considered a machine that continually absorbs and emits radiation and there are millions of them in an atomic nucleus.
You can try to imagine how small a basic nucleus is and it all takes place constantly with the speed of light.
It is also the basic nucleus which transforms the energy to radiation in connection with a particle´s deceleration and it is the one part which forms the the molecular binding structure.

The basic nucleus is only stable in free standstill at the speed of light c
The basic nucleus is responsible for all radiation, so it is the one that determines the max. and min. of the radiation size

Technical and mathematical sizes
The max. radiation value is 5.185681022 * 10-34kg or 4.6606576 * 10 -17joul
The min.. radiation value is greater than 0 joul
Al radiation lies within this range and is an entire light beam.

Technical provision of Planck constant
E base = (V basis * c 2) * c 2
When a particle decelerate dv, will basic nuclei redistribute the kinetic energy.

E Kinetic = (V basis * dv 2) * c 2 E Kinetic = (V basis * c 2) * dv2
We are then given dv2 = v (frequency) = h merke = m basis = (V basis * c 2 )

The constant is technically determined and is one of the universe's basic elements which I will not deviate from.
A deviation will affect other important construction parts.
The constant is therefore technical specific to 5.185681022 * 10 -34 kg * s.

without there being blended something measuring equipment into it.See also.

Planck's constant h = 6.62606896 * 10 -34 J * s. Device name is wrong
Planck's constant h = 6.62606896 * 10 -34 kg * s = E photon = (h * v ) J * s
The reason is probably that they see light as a wave and a wave does not have any mass.

Photon internal structure
When a particle decelerates the basic nuclei are supplied energy with the speed dv2
The basic nucleus can not contain two different values of the speeds (dv2) and we get a compression to the highest value c2. The volume is reduced and the speed increases to c.
There is nothing new in compression, we know it from the big bang.

m basis2 = (V basis * c 2) + (V basis* dv 2) = m basis2= (V basis * c 2) + (V photon * c 2)

If the basic nucleus could not transform kinetic energy by compression, the nucleus would not be ableto emit a light beam with the velocity c
All light beams has the velocity c, it is the volume of the light beam which forms the light beam´s diameter.
It is the light beam is diameter that ineracts with a force field and make sure we get a deflection.
If the basic nucleus is in rest in proportion to the universe is coordinates (0,0,0) and emits one light beam is the string length c.

If the nucleus is moving toward or away from the photon is emission line the string length will be longer or shorter and get another string diameter and another deflection when it interacts in a force field,

The phenomenon is observed as a displacement in the line spectrum, also called red and blue displacement
Notes kinetic energy and radiation

Ex. a proton consists of about 3.2 million basic nuclei which are bound together and forms the whole mass of the proton. When the proton deaccelerates all the basic nuclei as the proton consists of will be allocated the energy mbasis = Vbasis * dv2.
The energy´s redistributed between the basic nuclei before they are emitted as radiation, therefore we get many different emission wavelengths.

Therefore, we can not make a calculation for the individual wavelengths, but only the mean value, which is also called black body radiation of the individual particle.

If you want to do some tests with deflection of a light string in a force field, you must first calculate the light string diameter and determine the distance between the atomic nuclei as shown in Fig. F32
You need a set of formulas for mass attraction and put a computer simulated model up. I would not recommend that you use the old heavy mass attractiveness formulas, but instead use the new light formulas

The Universe.

Classic big bang.

Mass formation.

Atom structure.

Atom binding.

Molecular binding.

Particle radiation

Magnetic fields.



Micro physics


Sidst opdateret : 01 march 2017
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